WebSep 4, 2024 · From given information, the enthalpy change for the combustion of 2.00 grams of propane is -102.5 kj. It asks to calculate the enthalpy change in same conditions for the combustion of 1 mole of propane. We convert 1 mole of propane to grams using molar mass(44.1 gram per mol) and then calculate the heat using the given information … WebAug 6, 2024 · Calculate the standard enthalpy of combustion of propane Given the following data (1) C(s) + O2(g) ==> CO2(g) ΔHθ = -393 kJ/mol-1 (2) H2(g) + 1/2O2(g) ==> H2O(l) …
chapter 6 Thermochemistry textbook questions Flashcards
WebNov 12, 2024 · The combustion of propane (C₃H₈) produces 2220 kJ of energy per mole of propane consumed. What mass in grams of propane will be required to heat 63.0 gal of bathtub water from 25.0°C to 35.0°C if the process is 80.0% efficient? (1 gal = 3.785 L, 1 cal = 4.184 J, the density of water is 1.00 g/mL, the specific heat of water is 1.00 cal/(g°C)? WebSep 9, 2024 · Generators to use 2-3 gallons of propane per hour; Fireplaces to use 1-3 gallons of propane per hour; The Average Cost of Propane Per Year. The average cost of propane per year (for homes … how do you work out linear meters
5.72 Calculate the enthalpy of combustion of propane, …
WebThe standard enthalpy of combustion of n-propane is -2220 kJ mol-1 at 25°C. From this information and enthalpy of formation data for CO,(g) and H,0(g), calculate the enthalpy of formation of n-propane. The enthalpy of formation of propene is +20.42 kJ mol-1. Calculate the enthalpy of hydrogenation of propene to propane. WebGive detailed Solution (Don't use Ai for answering this. Transcribed Image Text: Consider the combustion of propane, C3H8: C3H8 (g) + 5 O2 (g) → 3 CO2 (g) + 4 H2O (1) ArH = -2,220.0 kJ mol-1 How much heat is released at constant pressure, in units of kJ, from the complete combustion of propane if 1.00×102 L (1.00 m3) of CO2 is produced at 1. ... WebOct 7, 2024 · 2.5000g ⋅ 1 mole C3H8 44.1g = 0.0566893 moles C3H8 SInce you know that when 0.0566893 moles of propane undergo combustion, 115.75 kJ of heat are being released, you can say that when 1 mole of propane undergoes combustion, the reaction will give off 1mole C3H8 ⋅ 115.75 kJ 0.0566893moles C3H8 = 2041.8 kJ how do you work out ka from pka